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answers
Exercise 1
1. Answer:
30 days.
Explanation:
Before:
One day
work
= 1 / 20
One man’s
one day work =
1 / ( 20 * 75)
Now:
No. Of workers
= 50
One day work = 50 * 1 / ( 20 * 75)
The total no. of days required to complete the work = (75 * 20) / 50 = 30
2. Answer:
0 %
Explanation:
Since 3x / 2 = x / (2 / 3)
3. Answer:
5.3 %
Explanation:
He sells 950 grams of pulses and gains 50 grams.
If he sells 100 grams of pulses then he will gain (50 / 950) *100 = 5.26
4. Answer:
250 lines of codes
5. Answer:
7 days
Explanation:
The equation portraying the given problem is:
10 * x – 2 * (30 – x) = 216 where
x is the number of working days.
Solving
this we get x = 23
Number of days he was absent was 7 (30-23) days.
6. Answer:
150 men.
Explanation:
One day’s
work
= 2 / (7 * 90)
One hour’s
work
= 2 / (7 * 90 * 8)
One man’s work = 2 / (7 * 90 * 8 * 75)
The remaining work (5/7) has to be completed within 60 days, because the total number of days allotted for the project is 150 days.
So we get the equation
(2 * 10 * x * 60) / (7 * 90 * 8 * 75) = 5/7 where x is the number of men working after the 90th day.
We get x = 225
Since we have 75 men already, it is enough to add only 150 men.
7. Answer:
(c) 1
Explanation:
a percent of b : (a/100) * b
b percent
of a : (b/100) * a
a percent of b divided by b percent of a : ((a / 100 )*b) / (b/100) * a )) = 1
8. Answer:
Cost price of horse = Rs. 400 & the cost price of cart = 200.
Explanation:-
Let x
be the cost price of the horse and y be the cost price of the cart.
In the first sale there is no loss or profit. (i.e.) The loss obtained is equal to the gain.
Therefore (10/100) * x = (20/100) * y
X = 2 * y
-----------------(1)
In the second sale, he lost Rs. 10. (i.e.) The loss is greater than the profit by Rs. 10.
Therefore (5 / 100) * x
= (5 / 100) * y + 10 -------(2)
Substituting (1) in (2) we get
(10 / 100) * y = (5 / 100) * y + 10
(5 / 100) * y = 10
y = 200
From (1) 2 * 200 = x = 400
9. Answer:
3.
Explanation:
Since inclusion of any male player will reject a female from the team. Since there should be four member in the team and only three males are available, the girl, n should included in the team always irrespective of others selection.
10. Answer:
5
11. Answer:
1,2,3 & 4
12. Answer:
B
13. Answer:
11 & 9 apples per tree.
Explanation:
Let a,
b, c, d & e be the total number of apples bored per year in A, B, C,
D & E ‘s orchard. Given that
a + 1 = b + 3 = c – 1 = d + 3 = e – 6
But the question is to find the number of apples bored per tree in C and
D ‘s orchard. If is enough to consider c – 1 = d + 3.
Since
the number of trees in C’s orchard is 11 and that of D’s orchard
is 13. Let x and y be the number of apples bored per tree in C & d ‘s
orchard respectively.
Therefore
11 x – 1 = 13 y + 3
By trial and error method, we get the value for x and y as 11 and 9
14. Answer:
G.
Explanation: